One method used to produce soap, NaC17H35CO2, includes the reaction between NaOH and animal fat, C3H5(C17H35CO2)3 according to this balanced chemical equation:
C3H5(C17H35CO2)3 + 3NaOH = C3H5(OH)3 + 3NaC17H35CO2
a) How many grams of soap would theoretically be produced by starting with 125 grams of fat?
b) If the actual amount of soap produced were 31 grams, what would be the percentage yield of the reaction?
Thank you.
Chem - Question about Stoichiometry
2008-10-27 2:19 pm
回答 (1)
2008-10-27 7:07 pm
✔ 最佳答案
a)C3H5(C17H35CO2)3 + 3NaOH → C3H5(OH)3 + 3C17H35CO2Na
C3H5(C fat CO2)3 + 3NaOH → C3H5(OH)3 + 3C17 soap
Mole ratio ffat : soap = 1 : 3
Molar mass of fat = 12x57 + 1x110 + 16x6 = 890 g mol-1
Molar mass of soap = 23 + 12x18 + 1x35 + 16x2 = 306 g mol-1
No. of moles of fat used = 125/890 mol
Theoretical no. of moles of soap formed = (125/890) x 3 mol
Theoretical mass of soap produced = [(125/890) x 3] x 306 = 129 g
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b)
Percentage yield = (31/129) x 100% = 24.0%
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