can anyone solve the following quadratic equation for x:
4000=48x^2-48x
quadratics help?????
2008-10-26 9:25 am
回答 (5)
2008-10-26 9:54 am
✔ 最佳答案
4000=48x^2-48xDividing by 16,
250 = 3x^2 - 16x
Or 3x^2 - 16x - 250 = 0
Or x = [-(-16) +- sqrt{(-16)^2 - 4*3*(-250)}]/(2*3)
Or x = [16 +- sqrt(156 + 3000)]/6
Or x = [16 +- sqrt(3156)]/6
Or x = [16 +- sqrt(4*789)]/6
Or x = [16 +- 2 * sqrt(789)]/6
Or x = 16/6 +- (2/6) * sqrt(789)
Or x = 8/3 +- (1/3) * sqrt(789)
2008-10-26 4:48 pm
4000 = 48x^2 - 48x
48x^2 - 48x - 4000 = 0
(48x^2 - 48x - 4000)/16 = 0/16
3x^2 - 3x - 250 = 0
x = [-b 屉(b^2 - 4ac)]/2a
a = 3
b = -3
c = -250
x = [3 屉(9 + 3000)]/6
x = [3 屉3009]/6
â´ x = [3 ±â3009]/6
48x^2 - 48x - 4000 = 0
(48x^2 - 48x - 4000)/16 = 0/16
3x^2 - 3x - 250 = 0
x = [-b 屉(b^2 - 4ac)]/2a
a = 3
b = -3
c = -250
x = [3 屉(9 + 3000)]/6
x = [3 屉3009]/6
â´ x = [3 ±â3009]/6
2008-10-26 4:33 pm
250 = 3x^2 - 3x
3x^2 - 3x - 250 = 0
3 ± â(9 + 3000)
-------------------- = x
..........6............
57.85.......-51.85
------- or .---------- = x
....6...............6
x = 9.64 or -8.64
3x^2 - 3x - 250 = 0
3 ± â(9 + 3000)
-------------------- = x
..........6............
57.85.......-51.85
------- or .---------- = x
....6...............6
x = 9.64 or -8.64
2008-10-26 4:32 pm
4000=48x^2-48x
subtract 4000 from both sides to get
48x^2-48x-4000=0
x=((-b)+/-sqrt(b^2-4ac))/2a (using the quadratic formula)
----->.......Good luck!
subtract 4000 from both sides to get
48x^2-48x-4000=0
x=((-b)+/-sqrt(b^2-4ac))/2a (using the quadratic formula)
----->.......Good luck!
2008-10-26 4:29 pm
48x^2 - 48x - 4000 = 0
參考: Use the Quadratic Formula to find the two solutions for x.
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