how do u solve for x in this problem?

3/7x + 5/7 = 2/3

Multiply through by x:
3/7 + 5x/7 = 2x/3

(3 + 5x)/7 = 2x/3

Multiply both sides by 7:
3 + 5x = 14x/3

Subtract 14x/3 from both sides:
3 + 15x/3 - 14x/3 = 0

3 + x/3 = 0

Subtract 3 from both sides:
x/3 = -3

Multiply both sides by 3:
x = -9



OR

(3/7)x + 5/7 = 2/3

Subtract 5/7 from both sides:
(3/7)x = 2/3 - 5/7

(3/7)x = 14/21 - 15/21

(3/7)x = -1/21

Multiply both sides by (7/3) NOTE: same as dividing by 3/7:
x = (-1/21)(7/3)

x = -1/9

ASSUMING that you mean :-

(3/7) x + 5/7 = 2/3

9x + 15 = 14

9x = - 1

x = - 1/9

PS
Should not have to assume !!!

3/7(x) + 5/7 = 2/3
3x/7 + 5/7 = 2/3
21(3x/7) = 21(2/3 - 5/7)
3(3x) = 7(2) - 3(5)
9x = 14 - 15
9x = -1
x = -1/9

3/7x+5/7=2/3 multiply by 21
9x+15=14 subtract 15
9x= -1 divide by 9
x = -1/9

Is the first term 3/7x or 3/7 of x?

Use brackets to make the question clear.

First multiply both sides of your equation by 7x giving:

1) 3 + 35x/7 = 3 + 5x = 14x/3 Now multiply both sides of 1) by 3:

2) 9 + 15x = 14x or 15x - 14x = -9 from which:

3). x = -9

3/7x+5/7=2/3
Multiply every term by the LCD, 21x
9 + 15x = 14x
15x - 14x = -9
x = -9

Easy, isns't it?

3/7x+5/7=2/3

Isolate 3/7x by subtracting 5/7 from both sides

3/7x+5/7 - 5/7 =2/3 - 5/7

3/7x = -1/21

Multiply both sides by the reciprocal of 3/7, which is 7/3

3/7 x * 7/3 = -1/21 * 7/3

x = -7/63

Good luck to you !

start by multiplying every thing by 21 so that you get rid of the fractions. example 5/7 times 21 =15

(3)/(7)*x+(5)/(7)=(2)/(3)

(3x)/(7)+(5)/(7)=(2)/(3)

(3x+5)/(7)=(2)/(3)

(3x+5)/(7)*7=(2)/(3)*7

3x+5=(2)/(3)*7

3x+5=(14)/(3)

3x=-5+(14)/(3)

3x=-(1)/(3)

(3x)/(3)=-(1)/(3)*(1)/(3)

x=-(1)/(3)*(1)/(3)

x=-(1)/(9)