wat is 7t+6-2(5+t/2)=5t-11?

7t+6-2(5+t/2)=5t-11
7t + 6 - 10 - 2t/2 = 5t - 11
7t - 4 - t = 5t - 11
7t - 5t - t = -11 + 4
t = -7

7t + 6 - 10 - t = 5t - 11
t = - 11 + 10 - 6
t = - 7

7t + 6 - 2(5 + t/2) = 5t - 11
7t + 6 - 2*5 - 2*t/2 = 5t - 11
7t + 6 - 10 - t = 5t - 11
7t - t - 5t = -6 + 10 - 11
t = -7

Work the parentheses first..
7t+6-(10+t)=5t-11 (2x5=10, 2x(t/2)=t
7t+6-10+t=5t-11
Then solve for all same
8t-4=5t-11
8t-5t=-11+4
3t=-7
t=-7/3 or -2 1/3
I think

use the Please Excuse My Dear Aunt Sally sign
1. P = Parentheses
2. E = Exponents
3. M = Multiplication
4. D = Division
5. A = Addition
6 S = Subtraction
YOU SHOULD HAVE AND ANSWER IF YOU FOLLOW *PEMDAS*

7t + 6 -2 ((10 +t )/2) = 5t -11
7t -10 -t = 5t -17
t = -27

i think... did it quick

haha its rong .. its -7 ><

t=-7