Make the p be the subject.
8PR = K - 4a (R-P)
Maths!!!
2008-10-23 5:33 am
回答 (2)
2008-10-27 5:57 am
8PR = K - 4a (R-P)
8PR = K- 4a(R) + 4a(P)
8PR - 4aP = K- 4aR
P(8R - 4a) = K- 4aR
P = (K- 4aR ) / (8R - 4a)
8PR = K- 4a(R) + 4a(P)
8PR - 4aP = K- 4aR
P(8R - 4a) = K- 4aR
P = (K- 4aR ) / (8R - 4a)
2008-10-23 5:39 am
8PR = K - 4a (R-P)
8PR = K- 4aR + 4aP
8PR - 4aP = K- 4aR
P(8R - 4a) = K- 4aR
P = (K- 4aR ) / (8R - 4a)
8PR = K- 4aR + 4aP
8PR - 4aP = K- 4aR
P(8R - 4a) = K- 4aR
P = (K- 4aR ) / (8R - 4a)
參考: me
收錄日期: 2021-04-23 23:00:57
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https://hk.answers.yahoo.com/question/index?qid=20081022000051KK01939