(5P+Q)x-4=Px+Q
唔知x係咩
FIND P同Q
可唔可以教我計(5P+Q)x-4=Px+Q
2008-10-23 2:56 am
回答 (5)
2008-10-23 3:36 am
✔ 最佳答案
(5P+Q)x-4=Px+Q by comparing coeft of constant
Q=-4
by comparing coeft of x
5P+Q=P
5P+(-4)=P
4P=4
P=1//
2008-10-23 4:02 am
(5P+Q)x-4=Px+Q
so, (5P+Q)x=Px, -4=Q
5P+Q=P , Q=-4
5P+(-4)=P
4P+(-4)=0
4P-4=0
4P=4
P=1
the answer is: P=1, Q=-4
so, (5P+Q)x=Px, -4=Q
5P+Q=P , Q=-4
5P+(-4)=P
4P+(-4)=0
4P-4=0
4P=4
P=1
the answer is: P=1, Q=-4
參考: my brain
2008-10-23 3:17 am
(5P+Q)x-4=Px+Q，FIND P同Q
(5P+Q)x-4=Px+Q
5Px+xQ-4=Px+Q
4Px+xQ-4=Q
4Px+xQ-4-Q=0
4Px +Qx -(4+Q) = 0
4Px +Qx=4+Q
x(4P+Q)=4+Q
x = (4+Q)/(4P+Q)
(5P+Q)x-4=Px+Q
5Px+xQ-4=Px+Q
4Px+xQ-4=Q
4Px+xQ-4-Q=0
4Px +Qx -(4+Q) = 0
4Px +Qx=4+Q
x(4P+Q)=4+Q
x = (4+Q)/(4P+Q)
2008-10-23 3:09 am
比較2邊的係數
(5P + Q)x - 4 = Px + Q
5P + Q = P
Q = -4
5P + (-4) = P
4P = 4
P = 1
(5P + Q)x - 4 = Px + Q
5P + Q = P
Q = -4
5P + (-4) = P
4P = 4
P = 1
2008-10-23 3:01 am
三個未知數要有三條式一得一條解唔到。
5Px + Qx -4 = Px +Q
4Px +Qx -(4+Q) = 0
x = (4+Q)/(4P+Q)
5Px + Qx -4 = Px +Q
4Px +Qx -(4+Q) = 0
x = (4+Q)/(4P+Q)
參考: CLOUDWAH
收錄日期: 2021-04-23 20:36:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081022000051KK01385