How would I go by solving this? : 6x+7>3+8x?
回答 (10)
2008-10-21 8:24 am
✔ 最佳答案
Solving an inequality is basically the same as solving an equation. There are some differences, but this one is straight forward.6x + 7 > 3 + 8x
Subtract 6x from both sides
7 > 3 + 2x
Subtract 3 from both sides
4 > 2x
Divide both sides by 2
2 > x
I prefer to have the variable on the left, so switch it and reverse the arrow.
x < 2
2008-10-21 3:24 pm
6x+7>3+8x
-2x>-4
x>2
-2x>-4
x>2
2008-10-21 6:52 pm
6x + 7 > 3 + 8x
6x - 8x > 3 - 7
-2x > -4
x < -4/-2
x < 2
6x - 8x > 3 - 7
-2x > -4
x < -4/-2
x < 2
2008-10-21 4:44 pm
Subtract 7 from each side
6x>-4+8x
Subtract 8x
-2x>-4
Divide by -2 ... remember if you divide by a negative, switch the signs
x<2
Hope this helps :)
6x>-4+8x
Subtract 8x
-2x>-4
Divide by -2 ... remember if you divide by a negative, switch the signs
x<2
Hope this helps :)
2008-10-21 3:51 pm
4 > 2x
2 > x
or
x < 2
2 > x
or
x < 2
2008-10-21 3:37 pm
6x+7>3+8x
4>2x
x<2
4>2x
x<2
2008-10-21 3:33 pm
The best thing to consider here is that the sign > makes no more difference in simplifying the equation than does an =. Simply move numbers around, changing their signs, and let "x > ___" be your answer, which is 2, according to the correct solutions already provided.
2008-10-21 3:26 pm
2x<4
x<2
x<2
2008-10-21 3:24 pm
6x+7>3+8x
3+8x<6x+7
8x-6x<7-3
2x<4
x<4/2
x<2(X is less than 2)
3+8x<6x+7
8x-6x<7-3
2x<4
x<4/2
x<2(X is less than 2)
2008-10-22 8:01 am
go to the tutoring center in your school.
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