點計???長細解答!!thx X100000000800000000789
更新1:
因式分解 -12x 2次方+36xy-27y 2次方 點計???
因式分解 問題!!thx x1000
回答 (3)
2008-10-28 12:50 am
✔ 最佳答案
44x 2次方-220xy+275y 2次方=44x^2-220xy+275y^2=275y^2-220xy+44x^2
=11(25y^2-20xy+4x^2)....抽公因式
=11[(5y)^2-2(5y)(2x)+(2x)^2].....用(a-b)^2= a^2-2ab+b^2
=11(5y-2x)^2
-12x 2次方+36xy-27y 2次方=-12x^2+36xy-27y^2
=-3(4x^2-12xy+9y^2)....抽公因式
=-3[(2x)^2-2(2x)(3y)+(3y)^2].....用(a-b)^2= a^2-2ab+b^2
=-3(2x-3y)^2
參考: 會考數學c既人~
2008-10-24 6:07 am
44x2-220xy+275y2
=11(4x2-20xy+25y2)
=11(2x-5y)2
12x2+36xy-27y2
=12x2+36xy+(-27y2)
=3[4x2+12xy+(-9y2)]
=3[2x+(-3y)]2
=3(2x-3y)2
=11(4x2-20xy+25y2)
=11(2x-5y)2
12x2+36xy-27y2
=12x2+36xy+(-27y2)
=3[4x2+12xy+(-9y2)]
=3[2x+(-3y)]2
=3(2x-3y)2
參考: 自己
2008-10-22 4:02 am
44x^2-220xy+275y^2
=11[(2x)^2-2(2x)(5y)+(5y)^2]
=11(2x+5y)^2
=11[(2x)^2-2(2x)(5y)+(5y)^2]
=11(2x+5y)^2
收錄日期: 2021-04-29 16:12:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081021000051KK01515