✔ 最佳答案
>>>1)A 2-dight number is divisble by both 2 and 5.Half this number is less than 6 times the tens dight of the number by 4.Find this 2-dight number.(use equation)
果個係digit, 係咪?
(1)首先假設左未知數先,
設 x 為這個數值的個位, y 為這個數值的十位
Let x be the lower digit and y be the tens digit.
換句話講, 呢個數既值就係 10x+y
(2)然後以x, y 表示題目的意思
"A 2-dight number is divisble by both 2 and 5."
有個兩位數, 可以被2同5除盡.
10x + y = 2 * 5K = 10K where K is a constant.
Therefore, y=0
"Half this number is less than 6 times the tens dight of the number by 4."
這個數值的一半比它的十位數值的6陪小於4.
10x / 2 = 6x + 4
5x = 6x + 4
x = 4
(3)"Find this 2-dight number"
Therefore, the 2-digit number is 40.
>>2)There are some chickens and rabbits in a cage.1/3 of the rabbits were born to have 3 legs.If the total number of heads is 35 and the total of legs is 90,find the number of
a.chickens(use equation)
b.rabbit with 4 legs
Let a be the number of the chickens and
b be the number of rabbits
total number of rabbit legs = b/3 * 3 + 2b/3 * 4 = 11b/3
total number of chicken legs = 2a
Therefore, 2a + 11b/3 = 90 -----------[1]
total number of heads = a + b = 35
so, a = 35 - b -------------------------[2]
Put [2] into [1],
2(35-b) + 11b/3 = 90
70 + 5b/3 = 90
5b/3 = 20
b = 12 ----------[3]
Put [3] into [2], a = 35 - 12 = 23
(a)There are 23 chickens.
(b)2(12)/3 = 8
There are 8 rabbits with 4 legs.