1.
11y-1=-7(2y-7)
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如果仲有我會慢慢加=]
中一數學-方程式
2008-10-21 6:28 am
回答 (6)
2008-10-22 2:39 am
✔ 最佳答案
11y-1=-7(2y-7)11y-1=(-14y)-(-49)
11y-(-14y)-(-49)=(-1）
11y+14y+49=(-1)
25y+49=(-1)
25y=(-1)-(+49)
25y=-1-49
25y=-50
y=-25/50
y=-2
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參考: me
2008-10-27 7:39 am
11y - 1 = -7 (2y - 7)
11y - 1 = -14y +49 [拆括號,負正得負,負負得正]
25y = 50 [調換後,負變正,正變負]
y = 2
---------------------------------------------------------------------------------
11y - 1 = -7 (2y - 7)
11y - 1 = -14y +49
11y -1 +14y = -14y +49 (+14y)
25y -1 (+1) = 49 +1
25y = 50
y = 2
11y - 1 = -14y +49 [拆括號,負正得負,負負得正]
25y = 50 [調換後,負變正,正變負]
y = 2
---------------------------------------------------------------------------------
11y - 1 = -7 (2y - 7)
11y - 1 = -14y +49
11y -1 +14y = -14y +49 (+14y)
25y -1 (+1) = 49 +1
25y = 50
y = 2
參考: Myself
2008-10-22 2:57 am
11y-1是一道完整的算式，不要管，先解-7(2y-7)。
-7(2y-7)
=(-7*2y)-(-7*7)
=-14y-(-49)
=-14y+49
-14y+49=49 (-14y)
=49-14y
所以答案是：
11y-1=-7(2y-7)
11y-1=-14y-(-49)
11y-1=-14y 49
11y=-14y 50
11y-(-14y)=50
25y=50
y=2
P.S：符號解釋，正正得正，負負得正，正負得負。
-7(2y-7)
=(-7*2y)-(-7*7)
=-14y-(-49)
=-14y+49
-14y+49=49 (-14y)
=49-14y
所以答案是：
11y-1=-7(2y-7)
11y-1=-14y-(-49)
11y-1=-14y 49
11y=-14y 50
11y-(-14y)=50
25y=50
y=2
P.S：符號解釋，正正得正，負負得正，正負得負。
2008-10-21 8:12 pm
11y - 1 = -7(2y-7)
11y - 1 = -14y +49
25y = 50
y = 2
11y - 1 = -14y +49
25y = 50
y = 2
2008-10-21 6:32 am
11y -1 +7 = -7 (2y-7) +7
11y + 6 = 2y -7
11y -2y +6 -6 = 2y -2y -7 -6
9y = -1
9y/9 = -1/9
y = -1/9
11y + 6 = 2y -7
11y -2y +6 -6 = 2y -2y -7 -6
9y = -1
9y/9 = -1/9
y = -1/9
收錄日期: 2021-04-21 13:31:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081020000051KK02166