4x-y=8 x+5y=44 solve by elimination method?

1. Add the first equation to the second equation 5 times in order to get rid of the y.

21x = 84
simplify to x = 4

2. Now you know what x is. Apply this to any of the equation.

(4x4)-y = 8
16-y = 8
-y = -8
y = 8

So x = 4 and y = 8

you will could multiply the equations so as that as quickly as they're extra jointly between the variables will cancel out: (4x - y = a million) * 6 24x - 6y = 6 x + 6y = 19 upload the hot equations into one yet another: 25x = 25 x = a million Now which you comprehend what x equals, use that to unravel for y: a million + 6y = 19 6y = 18 y = 3 ------------- common: x = a million y = 3 As an ordered pair: (a million, 3)

4x - y = 8
x + 5y = 44

x + 5y = 44
4(x + 5y) = 4(44)
4x + 20y = 176

...4x - y = 8
‒ 4x + 20y = 176 (subtraction)
------------------------------
-21y = -168

-21y = -168
y = -168/-21
y = 8

4x - y = 8
4x - 8 = 8
4x = 8 + 8
x = 16/4
x = 4

∴ x = 4 , y = 8

y = 4x - 8

x + 5 (4x - 8) = 44
x + 20x - 40 = 44
21 x + 84
x = 4

y = 8

4x-y=8 eqn1
x+5y=44 eqn2

rearrange eqn2 to get:

x = 44-5y

substitute this into eqn1 to eliminate x:
4x-y=8
4(44-5y) - y =8
176-20y-y=8
-21y = -168
y=8

now subst y = 8 into rearranged eqn:

x=44-5y
x=44-5*8
x=44-40
x=4

4x-y=8 converts to
4x-8=y replace the y value in the other equation with this

x+5(4x-8)=44 solve for x now
x+20x-40=44
x+20x = 84
21x=84
x= 84/21 x= 4

Plug the x back into the first equation
4*4-y =8
16-y = 8
16-8 -y= 8-8
8-y+y=y
8=y

Basically this is really simple algebra. So good luck on your homework. Don't just take my answer try to understand it or you will fail your next test. I haven't heard the term elimination method before, so I assume they mean solve for x and y.

Elimination just means multiply both equations by a constant to get one of the variables the same, the subtract or add the equations to cancel one. Don't forget to multiply the whole equation by that constant by the way.

12x+4y=44

It's not that hard...