Simplify the following expression (x to the 2– 9x – 36)/(x + 3) ?

(x^2 - 9x - 36)/(x + 3)
= (x^2 + 3x - 12x - 36)/(x + 3)
= [(x^2 + 3x) - (12x + 36)]/(x + 3)
= [x(x + 3) - 12(x + 3)]/(x + 3)
= (x + 3)(x - 12)/(x + 3) (cancel out x + 3)
= (x - 12)/1
= x - 12

= (x² - 9x - 36)/(x + 3)
= ([x - 12][x + 3])/(x + 3)
= x - 12

Answer: x - 12

x² - 9x - 36
-----------------
x + 3

(x - 12)(x + 3)
---------------------
x + 3

x - 12

x^2-9x-36
put x= -3
get 9 +27-36=0
x+3 is a factor
also put x=12
get 144-108-36=0
x-12 is a factor
so x^2-9x-36/(x+3)= (x+3)(x-12)/(x+3)= x-12

(x^2 - 9x -36) / (x+3)

[(x+3)(x -12)] / (x+3)

x - 12

(x-12)