Solve the following quadratic equation by a method of your choice: y to the 2 + 12y + 11 = 0. ?

y^2 + 12y + 11 = 0

Find two numbers that when multiplied together equal 11 and when added together equal 12. The numbers are 1 and 11, in this case. Now put them in the equation like this:

(y + 1)(y + 11) = 0

The opposite signs of the numbers you found are the y values.

y = -1, y = -11

I found this by factoring. The other methods you can use are the quadratic formula or completing the square. I always go with one of the first two (you can't factor all the time), since completing the square is more difficult, in my opinion.

( y + 11 ) ( y + 1 ) = 0

y = - 11 or y = -1

y^(2) +12y+11=0,y1=-6+(36-11)^1/2=-1,& y2=-11

2 + 12y + 11 = 0
-2 -2
12y + 11 = -2
-11 -11
12y = -13
divide by 12.
y = 13/12 = 1 1/12

? i have no clue, i just did algebra hahahah

It appears like the least complicated way is to component the expression. initiate with what you comprehend: (2x +- ??) (2x +- ??) as a results of actual actuality the consistent has an staggering signal, both signs and indications and signals interior the elements are an same. as a results of actual actuality the 'x' time period is unfavourable, they could both be minus signs and indications and signals. Now you've: (2x - ??) (2x - ??) you on the on the spot opt for 2 numbers which multiply to provide you the three for the consistent and upload as a lot as 4 to provide you the 4 for the 'x' time period. thinking the actual shown actuality that 3 and a million meet both one among those circumstances, the elements substitute into: (2x - 3) (2x - a million) both one among those expressions might want to equivalent 0 for the initial equation to be authentic. that provide you with 'x' values of three/2 for the first time period and a million/2 for the 2d.

y² + 12y + 11 = 0
(y + 11)(y + 1) = 0
y = - 11 , y = - 1

y^2 + 12y + 11 = 0
y^2 + 11y + y + 11 = 0
(y^2 + 11y) + (y + 11) = 0
y(y + 11) + 1(y + 11) = 0
(y + 11)(y + 1) = 0

y + 11 = 0
y = -11

y + 1 = 0
y = -1

∴ y = -11 , -1

y^2 + 12y + 11 = 0

I will do factoring.

(y+1)(y+11) = 0.

Equate to 0.

y + 1 = 0
y = -1

y + 11 = 0
y = - 11

{-1,-11}

if u just solve it algebraically...

12y+11+2=0
12y+13=0
12y= -13
y= -13/12

but i'm not entirely sure what you're asking....
Hope i helped a little! :]

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2+13 bring to da oher side
that be making 12y = -13
12y multiply to da oher side
y = 12 * -13
y = -156
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