A ball is thrown vertically upwards . After t seconds , its height (h m) above the ground is given by: h = 30t-5t^2
Find the values of t when the ball reaches half of the maximum height.
(Give your answers correct to 3 significant figures.)
中四數學題唷=.=............
2008-10-16 6:34 am
回答 (2)
2008-10-16 6:05 pm
h=-5(t^2 -6t)
h=-5(t^2 +(2)(t)(3) +3^2) +5(3)^2
h=-5(t+3)^2 +45
maximum height=45m
Hope I can help you.
h=-5(t^2 +(2)(t)(3) +3^2) +5(3)^2
h=-5(t+3)^2 +45
maximum height=45m
Hope I can help you.
參考: my maths knowledge
2008-10-16 6:37 am
h=-5(t^2 -6t)
h=-5(t^2 +(2)(t)(3) +3^2) +5(3)^2
h=-5(t+3)^2 +45
maximum height=45m
h=-5(t^2 +(2)(t)(3) +3^2) +5(3)^2
h=-5(t+3)^2 +45
maximum height=45m
參考: 自己
收錄日期: 2021-04-19 20:33:29
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