(x+4)^3次方-x^3次方
要因式分解
F.3數學題 ~~
2008-10-16 3:47 am
回答 (2)
2008-10-16 4:01 am
✔ 最佳答案
因式分解 :(x+4)3-x3
=[(x+4)-x][(x+4)2+(x+4)(x)+x2]
=4(x2+8x+16+x2+4x+x2)
=4(3x2+12x+16)//
2008-10-18 7:02 am
(x+4)3-x3
=[(x+4)-x][(x+4)2+(x+4)(x)+x2]
=4(x2+8x+16+x2+4x+x2)
=4(3x2+12x+16)
Hope I can help you.
=[(x+4)-x][(x+4)2+(x+4)(x)+x2]
=4(x2+8x+16+x2+4x+x2)
=4(3x2+12x+16)
Hope I can help you.
參考: my maths knowledge
收錄日期: 2021-04-19 20:33:59
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https://hk.answers.yahoo.com/question/index?qid=20081015000051KK01639