in the following function, find f '(a) for the given value of a :
f(x) = 1 - x^2 ; a = 2
唔識做A.maths
2008-10-15 3:49 am
回答 (3)
2008-10-15 4:01 am
✔ 最佳答案
f(x) = 1 - x2
f(a) = 1 - a2
f’(a) = -2a
At a = 2,
f’(a) = -2(2)
f’(a) = -4
=
2008-10-20 6:09 pm
002 的答案：
f'(a) = -2a 點解代入既時候唔見左個負號??????? 答案錯了 !!!!
f'(a) = -2a 點解代入既時候唔見左個負號??????? 答案錯了 !!!!
2008-10-15 4:11 am
We need to find the value of f'(a), so we should sub a into f(x)
f(a) = 1-a^2
f'(a) = (-)(2)(a)^1 次方拉出來乘，再乘a^1（原本次方減一次）
f'(a) = -2a
Sub a as 2
so f'(a) = 2*2
= 4
f(a) = 1-a^2
f'(a) = (-)(2)(a)^1 次方拉出來乘，再乘a^1（原本次方減一次）
f'(a) = -2a
Sub a as 2
so f'(a) = 2*2
= 4
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