Maths probability

2008-10-13 3:54 am
Please answer the following question

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回答 (1)

2008-10-13 4:19 am
✔ 最佳答案
Denote:
B = the orange is bad
N = the orange is not bad

(a)
P(one of the oranges is bad)
= P(BNN) + P(NBN) + P(NNB)
= 3 x 0.04 x (1 - 0.04)2
= 0.110592

(b)
P(at least one of the oranges is bad)
= 1 - P(NNN)
= 1 - (1 - 0.04)3
= 0.115264
=


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