a 10kg rock is hung at the end of a rope of length 3.0m. the breaking tension of the
rope is 200N. the rope is now pulled through an angle x and released. if the rope is not to break, what is the maximum value of x?
AL.PHYSICS Q CIRCULAR MOTION
2008-10-12 10:59 pm
回答 (1)
2008-10-12 11:28 pm
✔ 最佳答案
For the rock undergoing circular motion at the lowest point.T - mg = mv2 / r
200 - 10(10) = 10v2 / 3
v2 = 30
Hence, by conservation of energy
P.E. lost = K.E. gained
mgr(1 - cosx) = 1/2 mv2
10(3)(1 - cosx) = 1/2 (30)
1 - cosx = 1/2
cosx = 1/2
x = 60*
So, maximum value of x is 60*.
參考: Myself~~~
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