can anyone help me solve this math problem x(7+x)=-12?

x(7 + x) = -12

Distribute the x:
7x + x^2 = -12

x^2 + 7x + 12 = 0

(x + 4)(x + 3) = 0

x + 4 = 0
x = -4

x + 3 = 0
x = -3

x = -3 or -4

Check:
-3(7 + (-3)) = -12
-3(4) = -12
-12 = -12
CHECK

-4(7 + (-4)) = -12
-4(3) = -12
-12 = -12
CHECK

x² + 7x + 12 = 0
(x + 4)(x + 3) = 0
x = - 4 , x = - 3

x(7 + x) = -12
x*7 + x*x = -12
x^2 + 7x + 12 = 0
x^2 + 3x + 4x + 12 = 0
(x^2 + 3x) + (4x + 12) = 0
x(x + 3) + 4(x + 3) = 0
(x + 3)(x + 4) = 0

x + 3 = 0
x = -3

x + 4 = 0
x = -4

∴ x = -4 , -3

First put your equation in the form ax^2 + bx + c = 0. Perform the indicated multiplication to get
1). 7x + x^2 = -12. Rearrange the terms to get
2). x^2 + 7x + 12 = 0. You now have the equation in the desired form with a = 1, b = 7, and c = 12.

You can now apply the standard quadratic solution formula:
3) x = (-b + or - sqrt(b^2 - 4ac))/2a. Your quadratic equation has two solutions. One is obtained.by using the + sign and the other is obtained by using the minus sign.

Suppose you use the plus sign in 3) and get a "zero" of the equation which can be designated xsub1. Using the minus sign gives you a second "zero" which can be designated xsub2. These are sometimes called "zeros" because if they are substituted for x in the original equation, the equation is satisfied.

After you have gone through the exercise described above, you can be sure that (x - xsub1) and (x - xsub2) are factors of the original equation.

One must be careful because, in general, these "zeros" may real and rational, real and irrational, or may be complex conjugates.

Based on the nature of your question, it may be presumed that you were not familiar with the quadratic solution formula set forth in 3) above. If you want to look into the derivation of this formula, ask on this website and you will get multiple answers.

it tooo tough

7x+x^2 + 12 = 0

therefore (x+4)(x+3)=0


therefore x=-4, -3

You must first distribute numbers. Example: 2(x + y) = 2x + 2y

so x(7+x) = -12
---> 7x + x^2 = -12
---->x^2 + 7x + 12 = 0 <------to put into quadratic formula form

then solve it out.
(x + 4)(x + 3)
x = -4 or -3