math&phy questions

2008-10-12 2:24 am
我唔知點計二元一次方程,有咩方法可以計

同s=ut+1/2at^2
e.g.5=10t+1/2(-10)t^2 點計

要解釋詳盡,thx
更新1:

我唔知幾時用邊條式

回答 (1)

2008-10-15 2:18 am
✔ 最佳答案
5=10t-5t^2
5t^2-10t+5=0
use formula: (a-b)^2 = a^2 - 2ab +b^2

(t*sqrt5 - sqrt5)^2 = 0

t*sqrt5 = sqrt5

t=1


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