multiply radical 5x^2y by radical 25xy^6?
回答 (4)
2008-10-10 5:18 pm
✔ 最佳答案
multiplying same root can be combinedsqrt 5x^2y * sqrt 25xy^6 = sqrt (5x^2y * 25xy^6)
sqrt 5x^2y * sqrt 25xy^6 = sqrt ( 5*25 * x^2*x * y*y^6)
sqrt 5x^2y * sqrt 25xy^6 = sqrt (125x^3y^7)
sqrt 5x^2y * sqrt 25xy^6 = 5xy^3 sqrt( 5xy)
2008-10-10 5:29 pm
â(5x^2y) * â(25xy^6)
= â[5 * x^2 * y] * â[5^2 * x * (y^3)^2]
= xâ(5y) * 5y^3âx
= 5xy^3â(5xy)
= â[5 * x^2 * y] * â[5^2 * x * (y^3)^2]
= xâ(5y) * 5y^3âx
= 5xy^3â(5xy)
2008-10-10 5:19 pm
sqrt(125x^3y^7)
=5xy^3 sqrt(5xy)
=5xy^3 sqrt(5xy)
2008-10-10 5:21 pm
5x^2y by radical 25xy^6
x rad 5y times 5y^3 rad x
5xy^3 rad 5xy
x rad 5y times 5y^3 rad x
5xy^3 rad 5xy
收錄日期: 2021-05-01 11:20:27
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