f.4 mathz,

2008-10-11 7:31 am
Given that the sum of 2 positive numbers is 10, find the 2 numbers so that the sum of the squares is a minimum.

回答 (2)

2008-10-11 6:40 pm
✔ 最佳答案
let the number be x and the other number be (10-x) and the sum of the squ. of these two numbers be y.
the sum of the squ.
y=x^2+(10-x)^2
y=x^2+x^2-20x+100
y=2x^2-20x+100
by completing the squ.
y=2(x^2-10x+50)
y=2(x^2-10x+5^2+50-5^2)
y=2(x-5)^2+50

so the minimum value of y is 50.
so the minimum value of the sum of the squ. of these two numbers is 50.
參考: me
2008-10-11 7:45 am
Let the no.s are n and (10-n)
by considering, n^2+(10-n)^2=2(n^2-10n+50)
=2(n-5)^2+50
the minimum value is 50
參考: ME


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