✔ 最佳答案
The person probably has landed on bushes with soft soil, or landed on surfaces covered with thick snow.
The speed of the person before hitting the ground depends on the height at which he jumps. Suppose the person reaches a speed of 100 km/h (=28 m/s) before touching the ground, and assume a person is of mass 60 kg and could tolerate a decceleration of 3g, say (i.e. 3x10 m/s2), then
the momentum of the person before hitting the ground = 60 x 28 Ns = 1680 Ns
For a decceleration of 3g, the net force acting on the man is = 60 x 3g N = 180g N = 1800 N
The decceleration time = 1680/1800 s = 0.9 s
That is, if the person collides with trees and bushes and eventually lands on soft soil, the duration could be as long as 1 second. In that case, he wouldn't be killed provided that he is able to tolerate the 3g decceleration.