中一方程式

2008-10-10 1:19 am
1)-2(y-7) =7y-4
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2)4(y+3) = -8(y-6)
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3)-5(y-2)-9 = 3(y-13)
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4) 9分之12-14z =15+3z
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5)6分之-(7z+4) = 3分之26
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6)11分之14-9z = 7分之z+8

回答 (3)

2008-10-10 2:11 am
✔ 最佳答案
2)4(y 3) = -8(y-6)
4y 12=-8y 48
4y 8y=48-12
12y=36
y=3
3)-5(y-2)-9=3(y-13)
-5y 10-9=3y-39
-5y 1=3y-39
-5y-3y=-39-1
-8y=-40
y=5

2008-10-09 18:17:52 補充:
4)9分之12-14z =15+3z
12-14z=135+27z
-14z=135-12+27z
-14z-27z=123
-41z=123
z=-3
5)6分之-(7z+4) = 3分之26
-(7z+4) =26(2)
-7z-4 =52
-7z =52+4
-7z =56
z =-8
2008-10-10 1:33 am
1)-2(y-7) =7y-4
-2y+14=7y-4
-9y=-18
y=2

2)4(y+3) = -8(y-6)
4Y+12=-8Y+48
12Y=36
Y=3

3)-5(y-2)-9 = 3(y-13)
=
=
=

4) 9分之12-14z =15+3z
12-14z=135+27z
-123=41z
z=3

5)6分之-(7z+4) = 3分之26
-(7z+4) = 26*2
-7z=56
z=8

6)11分之14-9z = 7分之z+8
7(14-9z)=11(z+8)
98-63z=11z+88
87z=151
z=151/87
2008-10-10 1:23 am
1)-2(y-7) =7y-4
  -2y+14=7y-4
  -2y-7y=-4-14
   -9y=-18
   y=2


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