Urgent!! Math Question differentiation (15)

總結一下,就是這樣:
1 = cos (xy^2)[ d(xy^2)/dx]
1 = cos(xy^2)[ 2xyy' + y^2]
1 = 2xycos(xy^2)y' + y^2cos(xy^2)
y' = [1- y^2cos(xy^2)]/[ 2xycos(xy^2)].
1 + x = sin ( xy^2 )
0+1 = cos(xy^2)(x2y(dy/dx)+y^2(1))
x2y(dy/dx)+y^2 = 1/cos(xy^2)
x2y(dy/dx) = 1/cos(xy^2)-y^2
x2y(dy/dx) = (1 - y^2 cos(xy^2))/cos(xy^2)


ok?
希望幫到你

1 = cos (xy^2)[ d(xy^2)/dx]
1 = cos(xy^2)[ 2xyy' + y^2]
1 = 2xycos(xy^2)y' + y^2cos(xy^2)
y' = [1- y^2cos(xy^2)]/[ 2xycos(xy^2)].