✔ 最佳答案
1/[24(y x^2)] – 1/[6(xy^2)]
= 1[6(xy^2)] / [24(y x^2)] [6(xy^2)] – 1[24(y x^2)] / [6(xy^2)] [24(y x^2)]
= [ (xy^2)] / [24(y x^2)] [(xy^2)] – [4(y x^2)] / [(xy^2)] [24(y x^2)]
= [(xy^2) –4(y x^2)] / [24(y x^2)] [(xy^2)]
= xy[(y) –4(x)] / [24xy(y^2 x^2)]
= [y –4x] / [24 (x^2y^2)]
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