Your chum is optimal 6x^2 - 2x = 0 x is a basic element, so take an x out x(6x - 2) = 0 Now, set the two factors equivalent to 0 x = 0 6x - 2 = 0 sparkling up for x x = 0 6x - 2 = 0 6x = 2 x = 2/6 x = a million/3 The x-intercepts would be 0 and a million/3, like your chum pronounced. EDIT: particular, you're astonishing, a is 6 and b is -2, purely replace x = -b/2a x = -(-2)/2(6) x = 4/12 x = a million/3, this is the x-coordinate of the vertex Now, replace this into the equation to locate the y-coordinate. 6x^2 - 2x = y 6(a million/3)^2 - 2(a million/3) = y 6(a million/9) - (2/3) = y 2/3 - 2/3 = y 0 = y, the y-coordinate is 0 consequently, the vertex is (a million/3 , 0)
First thing to do is get the Xs all on one side and the numbers all on one side. Remembering that if something switches sides over the equals then it changes signs, so a 2 becomes a -2 for example.
So 6x-2=2x+6 becomes 6x-2x=2+6 then just cancel out normally :)