Quick Math Question..... Help plz..?

👨🏻‍🏫 學術台數學

iv23361512

2008-10-05 10:40 pm

The sum of an integer and 5 times its square is 234. Find the integer.
I want the solution and answer. Thx a lot...

更新1:

Um,,, i already know it is x+5^2=234. But the answer for this one is decimal. Not Integer. Anyone know why??

回答 (5)

[匿名]

2008-10-05 10:52 pm

✔ 最佳答案

x = integer

x + 5 * x^2 = 234
5x^2 + x - 234 = 0

Use the quadratic formula. Way too messy for me to type.

You find
x = ~6.74178
x = ~6.94178

What's problematic about this answer? It's not an integer. So, ya.

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[匿名]

2008-10-06 5:50 am

x+5(x^2)=234

No integer fits this equation

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[匿名]

2008-10-06 5:49 am

let x = an integer
5x^2 = t times its square
x + 5x^2 = 234

I'm sure you can do a little algebra yourself.

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[匿名]

2008-10-06 5:45 am

An integer x + 5x^2=234. Put it into ax^2+bx+c=0 and factor. You can do the work from there.

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[匿名]

2008-10-06 6:01 am

x+5sqrt(x)=234
solve for x
x=169
i put sqrt cause its the only way to get an integer answer. maybe this is what u or the book meant

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