有幾條負數方程想請各位幫幫忙:
2[2(x-4)+3}=5
2x-[3+(x-5)]=6
3x-[6-2(x-3)]=2(3-2x)
X=?
請各位好心人幫幫忙
好急架!!!
THX!
負數方程...急!!!(20點)
2008-10-06 12:05 am
回答 (3)
2008-10-06 12:10 am
✔ 最佳答案
2[2(x-4)+3]=52(x-4)+3=5/2
2x-8+3=5/2
2x=15/2
x=15/4//
2x-[3+(x-5)]=6
2x-(x-2)=6
x=4//
3x-[6-2(x-3)]=2(3-2x)
3x-(6-2x+6)=6-4x
3x-(12-2x)=6-4x
3x-12+2x=6-4x
9x=18
x=2//
2008-10-06 12:22 am
2[2(x-4)+3}=5
4x-16+6=5
4x=15
x=15/4
2x-[3+(x-5)]=6
2x-3-(x-5)=6
2x-3-x+5=6
x=4
3x-[6-2(x-3)]=2(3-2x)
3x-6+2x-6=6-4x
9x=18
x=2
4x-16+6=5
4x=15
x=15/4
2x-[3+(x-5)]=6
2x-3-(x-5)=6
2x-3-x+5=6
x=4
3x-[6-2(x-3)]=2(3-2x)
3x-6+2x-6=6-4x
9x=18
x=2
參考: 自己
2008-10-06 12:16 am
2[2(x-4)+3}=5
4x-16+6=5
4x=15
x=15/4
2x-[3+(x-5)]=6
2x-3-(x-5)=6
2x-3-x+5=6
x=4
3x-[6-2(x-3)]=2(3-2x)
3x-6+2x-6=6-4x
9x=18
x=2
4x-16+6=5
4x=15
x=15/4
2x-[3+(x-5)]=6
2x-3-(x-5)=6
2x-3-x+5=6
x=4
3x-[6-2(x-3)]=2(3-2x)
3x-6+2x-6=6-4x
9x=18
x=2
收錄日期: 2021-04-23 20:35:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081005000051KK01585