Help solving the equation by factoring!?

Listen, you cannot solve this by direct factorisation. Follow this method:

7t^2-15t+8=0

Here, a=7, b=-15, c=8

Now, D = (b^2)-(4*a*c) = 225-(4*7*8) = 225-224 = 1

Therefore, t = (b+sqrt(D))/(2*a) = (-15+sqrt(1))/(2*7) = -14/14 = -1

Again, t = (b-sqrt(D))/(2*a) = -16/14 = -8/7

Hopefully, the process is clear. Others have already worked out the answer. Alright, can you please tell me where is the square root sign on the keyboard? Its not on my laptop keyboard.

7t^2 - 15t + 8 = 0
7t^2 - 7t - 8t + 8 = 0
(7t^2 - 7t) - (8t - 8) = 0
7t(t - 1) - 8(t - 1) = 0
(t - 1)(7t - 8) = 0

t - 1 = 0
t = 1

7t - 8 = 0
7t = 8
t = 8/7

∴ t = 1 , 8/7

(7t - 8)(t - 1) = 0
7t = 8, t = 1
t = 8/7 , t = 1

You show great determination which will stand you in good stead in the long run.

7t^2-15t +8=0

7t^2-7t-8t+8=0

7t(t-1)-8(t-1)=0

(7t-8)(t-1)=0

t=8/7 or t=1

u must do quadractic equations

7t^2-15t+8=0 = Or (t -- 1)(7t -- 8) = 0 giving t = 7 or 8.

(7t-8)(t-1)=0

Eaither 7t-8=0 or t-1=0 in order for the left side to be 0

t=about 1.143
t=1

By factoring...
7t² - 15t + 8 = 0
(7t-8)(t-1) = 0
t = {8/7, 1}


OR you may use other methods...

A quadratic equation is in the form of ax²+bx+c. Use the quadratic formula to solve for the roots of the equation.

[-b±(√b²-4ac)] / 2a

15±1 / 14

Solution set: {8/7, 1}

OR

You may use the completing the squares method.

7t² - 15t + 8 = 0
t² - 15t/7+ 8/7 = 0
t² - 15t + 225/196 = -8/7
(t-15/14)² = 1/196
t - 15/14 = ±1/14
t = {8/7, 1}