(i-3)的五次方 乘以 (sin36度+i cos36度)的三次方 除以 (3+3i)的四次方=?
问题补充：答案是:8/81 cis(派/15)
你们可以告诉我,我可能把题目的个数字抄错了?
急!!!複數一問(高分20!!!!!!!!!!!!!)
2008-10-05 2:08 am
回答 (2)
2008-10-05 4:26 am
✔ 最佳答案
For ( -3 +i) , modulus is sqrt10, arg(161.56 degree).So ( - 3 + i)^5 = (sqrt 10)^5 arg( 161.56 x 5) = 100 sqrt 10 arg(87.825)......(1)
For (cos 36 + i sin 36), modulus is 1, arg ( 36).
So (cos 36 + i sin 36)^3 = 1 arg(36 x 3) = 1 arg ( 108)...... (2)
For (3 + 3i), modulus is sqrt 18, arg(45).
So ( 3 + 3i)^4 = 324 arg ( 180).............................(3).
So the answer = (1) x (2)/(3) = 100 sqrt 10/324 arg ( 87.825 + 108 - 180)
= 0.976 arg (0.276 radian).
2008-10-05 3:43 am
你沒有把题目的个数字抄错
收錄日期: 2021-04-25 22:35:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081004000051KK01914