f(x)=(x+1)^2,then f(x-1)=?
f(x)=x^2,thenf(x+y)-f(x-y)=?
MATH Question about function(easy)
2008-10-05 12:55 am
回答 (2)
2008-10-05 1:14 am
✔ 最佳答案
1) f(x)=(x+1)2f(x-1)=(x-1+1)2=x2
2) f(x)=x2
f(x+y)-f(x-y)= (x+y)2-(x-y)2= x2+2xy+y2-x2+2xy-y2= 4xy
參考: me
2008-10-05 5:36 am
Since f(x)=(x+1)^2
f(x+1) = [(x-1)+1]^2
=x^2
Since f(x)=x^2
f(x+y) - f(x-y)
=(x+y)^2 - (x-y)^2
=(2x)(2y) [ A^2-B^2 = (A+B)(A-B) ]
=4xy
f(x+1) = [(x-1)+1]^2
=x^2
Since f(x)=x^2
f(x+y) - f(x-y)
=(x+y)^2 - (x-y)^2
=(2x)(2y) [ A^2-B^2 = (A+B)(A-B) ]
=4xy
收錄日期: 2021-04-13 21:57:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081004000051KK01690