F.3 Chem Question~~~~{plz!! URGENT!!!}~~~~

2008-10-02 10:53 am
O, P, Q and R represent four elements of atomic numbers 10, 14, 17, 19 respectively.
a.)Which 2 of these elements would form an ionic compound?
b.)Hence,explain your answer.
------------ plz
圖片參考:http://tw.yimg.com/i/tw/ugc/rte/smiley_3.gif
-------------

回答 (1)

2008-10-02 6:13 pm
✔ 最佳答案
a)
Q and R would form an ionic compound.


b)
A metal and a non-metal form an ionic compound.

The electron arrangement of O is 2, 8.
O has 8 electrons in the outermost shell.
Hence, O is a noble gas and seldom forms compounds.

The electron arrangement of P is 2, 8, 4.
P has 4 electrons in the outermost shell.
Hence, P is a non-metal, but it is hardly to form ionic compounds (because it is hardly to gain or lose 4 electrons in the outermost shell).

The electron arrangement of Q is 2, 8, 7.
Q has 7 electrons in the outermost shell.
Hence, Q is a reactive non-metal, which can react with metals to form ionic compounds readily.

The electron arrangement of R is 2, 8, 8, 1.
R has 1 electron in the outermost shell.
Hence, R is a reactive metal, which can react with non-metals to form ionic compounds readily.
=


收錄日期: 2021-04-23 23:06:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20081002000051KK00228

檢視 Wayback Machine 備份