this is a perimeter question!?

P = L+L+W+W
or
2(L+W)

P=32<<given

L = 4W-9

So:

32= 4W-9+4W-9+W+W

32= 10W-18

10W= 50

W=5

sub back in: L = 4W-9

L= 20-9

L=11

2 x 11 + 2 x 5

22+ 10

=32

Answers are: length =11, width =5

2(L + B) = 32
L + B = 16
4B - 9 + B = 16
5B = 25
B = 5 ins
L = 11 ins

x = length
y = width

2(x + y) = 32 (solve by using substitution)
x = 4y - 9

2(x + y) = 32
(4y - 9) + y = 32/2
4y - 9 + y = 16
5y = 16 + 9
5y = 25
y = 25/5
y = 5

x = 4y - 9
x = 4(5) - 9
x = 20 - 9
x = 11

∴ x (length) = 11 (inches) , y (width) = 5 (inches)
(the dimensions are 11 x 5.)

Let l represent the length of the rectangle, and w represent the width of the rectangle.Then 4w is four times the width.
The formula for the perimeter of a rectangle is P = 2l + 2w
The length of the rectangle is nine inches less than four times the width, so l = 4w - 9. Substitute l = 4w -9 into the equation P = 2l + 2w, and the equation becomes P = 2(4w-9) + 2w
32 = P = 2(4w-9) + 2w
32 = 8w - 18 + 2w
32 = 10w - 18
add 18 to both sides:
50 = 10w
w = 50/10
w = 5
and l = 4w -9 = 4(5) - 9 = 11
The length of the rectangle is 11 inches and the width is 5 inches.

1st, let the width represented by 'w',
2nd, since length is 9inches less than 4w; length(l) = 4w -9

Perimeter = 2w + 2l
= 2w +2(4w-9)
= 10w-18
32= 10w-18
w=5inches
l= 4(5)-9
l= 11 inches

Have a nice dy ;D

Let x - the width of the rectangle
4x-9 - the length of the rectangle

The formula for the perimeter of a rectangle is
P = ( 2 * width) + (2 * length)

P = 2x + 2 (4x - 9)
32 = 2x + 2 (4x - 9)
32 = 2x + 8x -18
32 = 10x -18
50 = 10x
5 = x

width = x =5 in
length = 4x - 9 = 11in