how do you use square root PROPERTY to solve this equation? (2x+3)^2=25?

The square root property states that, whenever we take the square root of both sides, we have to include both positive and negative solutions. Represented verbally as "plus or minus", and looking like the symbol of a + on top of a - sign:

(2x + 3)^2 = 25

Take the square root of both sides, to get

2x + 3 = +/- 5

Solve for x.

2x = -3 +/- 5
x = (-3/2 +/- 5/2)

Which means

x = { (-3/2) + (5/2) , (-3/2) - (5/2) }
x = { (2/2) , (-8/2) }
x = { 1, -4 }

2x + 3 = ± 5
2x = - 3 ± 5
2x = 2 , - 8
x = 1 , - 4

Take the square root of both sides of the equation to get
2x + 3 = 5
Then x = 1

2a² + 8a = 5 2(a² + 4a ) = 5 ...a million/2(4) then sq. this and upload on both area...on the right area you should upload 2*4 because of the component 2 outdoors the () on the right area 2(a² + 4a + 4) = 5 + 2*4 2(a + 2)² = 13 the sq. is now carried out now remedy (a + 2)² = 13/2 a + 2 = ±?(13/2) a = -2 ± ?(13/2) which is also written as a = -2 ± ?(26) / 2 ~~

(2x + 3)^2 = 25
2x + 3 = ±√25
2x + 3 = ±5

2x + 3 = 5
2x = 5 - 3
2x = 2
x = 2/2
x = 1

2x + 3 = -5
2x = -5 - 3
2x = -8
x = -8/2
x = -4

∴ x = -4, 1

(2x+3)² = 25
5² = (-5)² = 25

take square root of both sides of equation
2x+3 = ±5

2x = -3 ± 5
x = -3/2 ± 5/2

x₁ = 1
x₂ = -4

2x + 3 = 5 or 2x + 3 = -5

=> x = 1 or x = -4

Applying square root we have
2x + 3 = 5 or 2x + 3 = -5
so x = 1 or x = -4