solve -4[x-2(2x-3)]+1=2x-3?

-4[x-2(2x-3)]+1=2x-3

-4[x-2(2x-3)]+1=2x-3
-4 [ x - 4x + 6 ] + 1 = 2x - 3
-4x +16x - 24 + 1 = 2x - 3
12x - 23 = 2x - 3
-2x -2x
-------------------------------
10 x - 23 = - 3
+3 + 3
-------------------------
10 x - 20 = 0


SOLVING:
10 x - 20 = 0
+20 +20
------------------------
10x = 20
10x/10 = 20/10
x = 2


CHECK WORK
-4[x-2(2x-3)]+1=2x-3
-4[(2)-2(2(2)-3)]+1=2(2)-3
-4 [ 0 ] + 1 = 4 - 3
0 + 1 = 1
1 = 1

Disagree with siberian. this can artwork with particular equations, yet you're forgetting that when you're taking the sq. root of something, the reply's both useful and damaging. utilising 2 plus-minus signs and indicators in an equation like that's discouraged. The information is that in this equation, you'll purely get one answer the position 2 are needed. in case you're taking the sq. root of both area of (2x ? 4)² = (x + 3)², you'd be left with ±(2x ? 4) = ±(x + 3). the subsequent step is kinda demanding to guess. you may nevertheless say that this equation spilts into (±(2x ? 4) = x + 3) v (2x ? 4 = ±(x + 3)) (±2x ± ?4 = x + 3) v (2x ? 4 = ±x ± 3) (?x ± 2x = 3 ± 4) v (2x ± ?x = 4 ± 3) ({a million, ?3}x = {7, ?a million}) v ({a million, 3}x = {7, a million}) x = {a million/3, 7} yet that's plenty messier and complicated than what others suggested.

- 4 [ x - 4x + 6 ] + 1 = 2x - 3
- 4 (6 - 3x) + 1 = 2x - 3
- 24 + 12x + 1 = 2x - 3
10x = 20
x = 2

Question very clearly presented by correct use of brackets---well done.

-4[x - 2(2x - 3)] + 1 = 2x - 3
-4[x - 2*2x + 2*3] + 1 = 2x - 3
-4[x - 4x + 6] + 1 = 2x - 3
-4[-3x + 6] + 1 = 2x - 3
12x - 24 + 1 = 2x - 3
12x - 2x = 23 - 3
10x = 20
x = 20/10
x = 2

-4[X- 4X+6] + 1 = 2X - 3 Multiply -2 to ( 2x-3)
-4[-3X+6] + 1 = 2X -3 Combine like terms

12X - 24 +1 =2X - 3 Multiply 3X+6 by -4
Subtract 2x from both side of the equation
10X - 23 = -3 Add 23 to both side of the equation

10X = 20 Isolate the variable - divide both side of
the equation by 10

X=2