Can you prove that 1+1=3?

[匿名]

2008-09-29 6:40 pm

✔ 最佳答案

It can sometimes happen when you round numbers.
Say x = 1.4, y = 1.4, then z = x+y = 1.4 + 1.4 = 2.8
Then if you round these numbers x = 1, y = 1, z = 3
So when looking at rounded numbers only, you may see:
x+y = z
1+1 = 3

This can sometimes happen when writing computer programs, and printing out rounded intermediate values.

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EDIT
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Here's a similar case where 1+1 = 1
x = 0.75, y = 0.6, z = x+y = 0.75+0.6 = 1.35
When rounded, you get
x + y = z
1 + 1 = 1

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An ESL Learner

2008-09-29 2:56 pm

1 + 1 = 3
(1 male + 1 female = 1 male, 1 female, 1 child)

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Avinash

2008-09-29 1:27 pm

1+1 = 11
In binary system 11 is the same as 3 of decimal system. ;)

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[匿名]

2008-09-29 1:10 pm

if 1 and + and 1 are objects...so 1 beside + beside 1 would be 3 objects ;))))

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[匿名]

2008-09-29 1:19 pm

if allowed division by 0
0 = 0
1^2 -- 1^2 = (3/2)^2 -- (3/2)^2
(1 + 1)(1 -- 1) = (3/2 + 3/2)(3/2 -- 3/2)
(1 + 1)*0 = 3*0
(1 + 1) = 3

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[匿名]

2016-12-15 8:59 pm

The others are perfect. just to characteristic slightly greater... a million + a million = 10 (in base 2) a million + a million = 2 (in base 3, 4, 5, 6 etc...) So i think of a million+a million=3 can by no skill be authentic, no count what base it somewhat is in.

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[匿名]

2008-09-29 1:44 pm

it is synergy, search "synergy"on the net.It can be possible...I mean 1+1=3

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[匿名]

2008-09-29 1:32 pm

Not in base 10 but in Binary yes..

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[匿名]

2008-09-29 1:23 pm

No, because it doesn't! An argument that involves dividing by zero, illustrates why we should never divide by zero - it doesn't make sense to do so. If you're ever given an argument that seems to show something like 1+1=3, the mistake is that somewhere there is a (possibly disguised) division by zero.

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[匿名]

2008-09-29 1:16 pm

Yes.
If you designate 1 the value of 1.5 (1=1.5) then 1.5+1.5=3.

Just algebra with numbers.

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