有a.maths 唔識!!

solution:
2x+y-8=0--------(1)
3x-y-2=0---------(2)
by sloving (1) and (2)
we get x=2 and y=4
so the intersection point of (1) and (2) is (2,4)
as x=2 is parallel to y-axis
therefore the answer is y=4

2x + y = 8.............(1)
3x - y = 2...............(2)
(1) + (2) we get
5x = 10
x = 2.
Therefore, the line passing through the intersecting point and perpendicular to the y -axis is x =2.