分解為因式
1) 3a+6
2) -12e+18f
3) -12ab+20bc-8b
F.3 分解為因式
2008-09-28 10:20 pm
回答 (4)
2008-09-28 10:24 pm
✔ 最佳答案
1) 3a+6=3a+3*2
=3(a+2)
2) -12e+18f
= -1*2*2*3e+2*3*3f
= (2*3)(-1*2e+3f)
= 6(3f-2e)
3) -12ab+20bc-8b
= -1*2*2*3ab+2*2*5bc-2*2*2b
= (2*2b)(-1*3ab+5bc-2b)
= (4b)(-3a+5c-2)
2008-09-28 10:23 pm
1)
3a+6
= 3(a + 2)
2)
-12e+18f
= - 6(2e - 3f)
3)
-12ab+20bc-8b
= - 4b(3a - 5c + 2)
3a+6
= 3(a + 2)
2)
-12e+18f
= - 6(2e - 3f)
3)
-12ab+20bc-8b
= - 4b(3a - 5c + 2)
參考: myself
2008-09-28 10:22 pm
1. 3(a+2)
2. 6(3f-2e)
3. 4b(5c-3a-2)
2. 6(3f-2e)
3. 4b(5c-3a-2)
收錄日期: 2021-04-23 23:07:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080928000051KK01209