F.3 分解為因式

2008-09-28 10:20 pm
分解為因式

1) 3a+6
2) -12e+18f
3) -12ab+20bc-8b

回答 (4)

2008-09-28 10:24 pm
✔ 最佳答案
1) 3a+6
=3a+3*2
=3(a+2)

2) -12e+18f
= -1*2*2*3e+2*3*3f
= (2*3)(-1*2e+3f)
= 6(3f-2e)

3) -12ab+20bc-8b
= -1*2*2*3ab+2*2*5bc-2*2*2b
= (2*2b)(-1*3ab+5bc-2b)
= (4b)(-3a+5c-2)
2008-09-28 10:25 pm
3(a+2)

6(-2e+3f)

4b(-3a+5c-2)
參考: me
2008-09-28 10:23 pm
1)
3a+6
= 3(a + 2)

2)
-12e+18f
= - 6(2e - 3f)


3)
-12ab+20bc-8b
= - 4b(3a - 5c + 2)
參考: myself
2008-09-28 10:22 pm
1. 3(a+2)
2. 6(3f-2e)
3. 4b(5c-3a-2)


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