✔ 最佳答案
1.
2NO(g) + O2(g) → 2NO2(g)
For gases under constant T and P, volume ratio = mole ratio
From the equation, volume ratio NO : O2 = 2 : 1
Actually, added volume ratio NO : O2 = 30 : 50 = 0.6 : 1
Hence, NO is the limiting reactant (completely reacted), and O2 is in excess.
Volume ratio NO : O2 = 2 : 1
NO is the limiting reactant (completely reacted).
Volume of NO reacted = 30 cm3
Volume of O2 reacted = 30 x (1/2) = 15 mL
Volume of O2 unreacted = 50 - 15 = 35 mL
Volume ratio NO : NO2 = 1 : 1
Volume of NO reacted = 30 mL
Volume of NO2 formed = 30 mL
Final volume
= Volume of O2 unreacted + Volume of NO2 formed
= 35 + 30
= 65 mL
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2.
Let V cm3 be the volume of H2 in the mixture.
Hence, volume of O2 in the mixture = (150-V) mL
2H2(g) + O2(g) → 2H2O(l)
At rtp, water exists as liquid and its volume is negligible.
For gases under constant T and P, volume ratio = mole ratio
Volume ratio H2 : O2 = 2 : 1
Volume of H2 reacted = V mL
Volume of O2 reacted = V/2 = 0.5V mL
Volume of O2 unreacted = 18.5 mL
Consider the total volume:
V + 0.5V + 18.5 = 150
1.5V = 131.5
V = 87.67
150-V = 62.33
In the mixture :
Volume of H2 = 87.67 mL
Volume of O2 = 62.33 mL
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