Applied maths Question 3題唔識點做

For Q. 3, you have left out some initial conditions.

2008-09-27 23:33:53 補充：

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2008-09-28 09:09:45 補充：
Finally, I got the question in Q.3 y(3) = 7
i.e. y = 7 when x = 3
From the expression, put y = 7, x = 3,
we get: 4 = Ae^[2/(-4)]
A = 4e^2
So, the particular solution is:
x - y = 4e^{2(x - 1)/(x-y)}