F.5 MATHS(coordinate treatment of simple locus problems)

Equation of L1:(y - 0) / (x - 0) = -1

x + y = 0

So, now we have the two equations:

L1: x + y = 0 ─── (1)

L2: 2x - y + 3 = 0 ─── (2)

To find the coordinates of A, we have to solve the two equations:

(1) + (2): 3x + 3 = 0, x = -1

Put x = -1 into (1):

y + (-1) = 0, y = 1

Therefore, the coordinates of A is (-1 , 1).