f.4,,amathz......
2008-09-27 11:31 pm
Show that the quadratic equation 2x^2 - 3(m-1)x + (m^2-4m-6)=0 has 2 unequal real roots in x.
回答 (1)
2008-09-27 11:38 pm
✔ 最佳答案
Δ=9(m-1)^2-4(2)(m^2-4m-6)=m^2 14m 57=(m 7)^2 8＞0so the equation has 2 unequal real root
2008-09-27 15:39:08 補充：
(m-7)^2-8
2008-09-27 15:40:22 補充：
(m+7)^2+8先
參考: me
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https://hk.answers.yahoo.com/question/index?qid=20080927000051KK01401