f.1數學問題.超急 請數學高手入

p 乘 2q 乘 3p 乘 q
p x 2q x 3p x q
= 3p3 x 2q2
= 6p3q2


(2 乘 A 減 3 乘 m) ( 5 乘 n 乘 n)
= (2A - 3m) (5n x n)
= 2a - 3m / 5n2 (冇得再計)


5b 減 2d 加 b 加 4d 减 3b
= 5b - 2d + b + 4d - 3b
= (5b + b - 3b) + (- 2d + 4d)
= 3b + 2d

The smallest number of three consecutive numbers is w.find their sum.
( 係 find their sum, 唔係 find their sun )
The sum
= w + (w + 1) + (w + 2)
= w + w + w + 1 + 2
= 3w + 3
可以 Factorize 佢做 : 3(w + 1)

2008-09-28 14:14:35 補充：
Sorry!!!!!!!!!!!!!!!

第一題應該係：

6p2q2

(我跟書中的題目&題號)(其實課後有答案)
Exercise 2A
2e:p×2q×3p×q
=2×3×p×p×q×q
=6p^2 q^2

2g:(2×L－3×m)÷(5×n×n)
=2L－3m/5n^2

3g:5b-2d b 4d-3b
=2d 4d 5b-b-3b
=6d 6b-3b
=6d 3b(書裏寫3b 2d,但我覺得錯)

6:w (w 1) (w 2)
=w w w 1 2
=3w 3
∴Their sum is(3w 3).

1.)6p²q²

2.)(2A-3m)/(5n²)

3.)3b+2d

4.)3w+3

2008-09-27 16:24:09 補充：
002,
第1題係冇3次gar
第2題唔駛括號嘅咩

2008-09-27 16:24:28 補充：
sor,係003,唔係002

1. 6p^2q^2

2. (2a-3m)÷(5n^2)

3. 5b-2d+b-4d-3b
=3b-6d

4. the smallest number is w , the next is w+1 and w+2
the sum of them is
w + (w+1) + (w+2)
3w+3

2008-09-27 15:41:22 補充：
3. 5b-2d+b+4d-3d
3b+2d

3p^2 x 2q^2

2a-3m
_____
5n^2

3b+2d

2008-09-29 16:40:49 補充：
3(w+1)