Find dy/dx of each of the following implicit functions.
2x^2 + √(xy) + y^2 = 10
f.5 amaths (1 question)
2008-09-26 3:54 am
回答 (3)
2008-09-26 4:26 am
✔ 最佳答案
The answer is as follows:圖片參考：http://i277.photobucket.com/albums/kk75/uncle_michael/20080925_mat_3.jpg?t=1222345512
2008-09-26 6:22 am
Differentiate the equation both sides [2x^2 + √(xy) + y^2 = 10]:
4x + (dy/dx) 0.5√(x/y) + 2y(dy/dx) = 0
dy/dx [0.5√(x/y) + 2y) = -4x
dy/dx = -4x / [0.5√(xy) + 2y]
4x + (dy/dx) 0.5√(x/y) + 2y(dy/dx) = 0
dy/dx [0.5√(x/y) + 2y) = -4x
dy/dx = -4x / [0.5√(xy) + 2y]
參考: me
2008-09-26 4:06 am
Differentiate the equation both sides [2x^2 + √(xy) + y^2 = 10]:
4x + (dy/dx) 0.5√(x/y) + 2y(dy/dx) = 0
dy/dx [0.5√(x/y) + 2y) = -4x
dy/dx = -4x / [0.5√(xy) + 2y]
4x + (dy/dx) 0.5√(x/y) + 2y(dy/dx) = 0
dy/dx [0.5√(x/y) + 2y) = -4x
dy/dx = -4x / [0.5√(xy) + 2y]
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