help help plz, Math Differentiation (10)

2008-09-25 9:26 pm

plz check ans for me, thank you

f(x) = (ax+b)/(cx+d)

f'(x) = (acx+da-ax-b)/ (cx+d)^2

am I correct?

any further simplify??

thank you!!

回答 (1)

2008-09-25 11:51 pm

✔ 最佳答案

f = (ax + b)/(cx + d)
f' = [(cx + d)(a) - (ax + b)(c)]/(cx + d)^2
= (acx + ad - acx - cb)/(cx + d)^2
= (ad - cb)/(cx + d)^2.

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