g(x) = x^1/2 multiply e^x
g'(x) = e^x [x^1/2 + 1/ (2x^1/2)]
Am I right? can I further simplify my ans?
sorry, kinda messy, thx!
收錄日期: 2021-04-25 22:39:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080925000051KK00580