How do you solve 49x^2-2940x+24500=0?
回答 (3)
2008-09-24 1:59 pm
✔ 最佳答案
49x² - 2940x + 24500 = 049(x² - 60x + 500) = 0
x² - 60x + 500 = 0
x² - 50x - 10x + 500 = 0
x(x-50) - 10(x-50) = 0
(x-10)(x-50) = 0
x = {10, 50}
2008-09-24 3:48 pm
49x^2 - 2940x + 24500 = 0
(49x^2 - 2940x + 24500)/49 = 0/49
x^2 - 60x + 500 = 0
x^2 - 10x - 50x + 500 = 0
(x^2 - 10x) - (50x - 500) = 0
x(x - 10) - 50(x - 10) = 0
(x - 10)(x - 50) = 0
x - 10 = 0
x = 10
x - 50 = 0
x = 50
∴ x = 10 , 50
(49x^2 - 2940x + 24500)/49 = 0/49
x^2 - 60x + 500 = 0
x^2 - 10x - 50x + 500 = 0
(x^2 - 10x) - (50x - 500) = 0
x(x - 10) - 50(x - 10) = 0
(x - 10)(x - 50) = 0
x - 10 = 0
x = 10
x - 50 = 0
x = 50
∴ x = 10 , 50
2008-09-24 2:00 pm
= 49(x^2 - 60x + 500) = 0
Divide thro by 49:
x^2 - 60x + 500 = 0
(x - 10)(x - 50) = 0
x = 10 or x = 50.
Divide thro by 49:
x^2 - 60x + 500 = 0
(x - 10)(x - 50) = 0
x = 10 or x = 50.
收錄日期: 2021-05-01 11:20:09
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