(x+y)^2-x-y

2008-09-24 11:10 pm

有條因式分解唔識做(x+y)^2-x-y，點計先岩？

回答 (5)

2008-09-24 11:22 pm

✔ 最佳答案

(x+y)2-x-y
=(x+y)2-(x+y)
=(x+y)[(x+y)-1]
=(x+y)(x+y-1)

👍 0 👎 0

2008-09-25 3:28 am

應該係咁,
=(x+y)^2-x-y
=(x+y)^2-(x+y) 抽左個負出黎,變左有(x+y) 所以就有得抽
=(x+y)((x+y)-1)

參考: me

👍 0 👎 0

2008-09-25 3:07 am

(x+y)2-x-y
=(x+y)2-(x+y)
=(x+y)[(x+y)-1]
=(x+y)(x+y-1)

參考: me

👍 0 👎 0

2008-09-25 12:22 am

(x+y)^2-x-y
=(x+y)^2-x-y
=x(x+y)

參考: me

👍 0 👎 0

2008-09-24 11:24 pm

(x+y)^2-x-y
=(x+y)^2-(x+y)
=（x+y)(x+y-1)

👍 0 👎 0