help subtract the polynomial ; (-11v^2+8v+3)-(7v^2+3)?
2008-09-24 6:43 am
2) what is polynomial for the perimeter and for the area of regutangle with y+3 as lenght and y as weith.
回答 (4)
2008-09-24 6:49 am
✔ 最佳答案
(-11v^2 + 8v + 3) - (7v^2 + 3)Distribute the (-):
-11v^2 + 8v + 3 - 7v^2 - 3
Regroup:
-11v^2 - 7v^2 + 8v + 3 - 3
Combine like terms:
-18v^2 + 8v
Perimeter of a rectangle (P) = 2 x length + 2 x width
P = 2(y + 3) + 2(y)
Distribute the 2:
P = 2y + 6 + 2y
Combine like terms:
P = 4y + 6
Area of a rectangle (A) = length x width
A = (y + 3) x (y)
A = y^2 + 3y
2008-09-24 4:35 pm
1)
(-11v^2 + 8v + 3) - (7v^2 + 3)
= -11v^2 + 8v + 3 - 7v^2 - 3
= -11v^2 - 7v^2 + 8v + 3 - 3
= -18v^2 + 8v
= -2(9v^2 - 4v)
= -2v(9v - 4)
2)
perimeter:
2(y)(y + 3)
= 2y(y + 3)
= 2y*y + 2y*3
= 2y^2 + 6y
area:
y(y + 3)
= y^2 + 3y
(-11v^2 + 8v + 3) - (7v^2 + 3)
= -11v^2 + 8v + 3 - 7v^2 - 3
= -11v^2 - 7v^2 + 8v + 3 - 3
= -18v^2 + 8v
= -2(9v^2 - 4v)
= -2v(9v - 4)
2)
perimeter:
2(y)(y + 3)
= 2y(y + 3)
= 2y*y + 2y*3
= 2y^2 + 6y
area:
y(y + 3)
= y^2 + 3y
2008-09-24 1:52 pm
-11v^2-7v^2+8v+3-3=-18v^2+8v= -2v(9v-4)
===================================================
perimeter=2(y+3+y)=4y+6,
area=y(y+3)=y^2+3y
===================================================
perimeter=2(y+3+y)=4y+6,
area=y(y+3)=y^2+3y
2008-09-24 1:48 pm
-18v^2 +8v
Peri = 2(y+3+y)=4y+ 6
area = (y+3)y=y^2 + 3y
Peri = 2(y+3+y)=4y+ 6
area = (y+3)y=y^2 + 3y
收錄日期: 2021-05-01 11:13:35
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